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標題:
maths
發問:
30,38,46,54的general term 係咩?
記T(n)為general term(通項), 則T(1) = 30 .....................(1) T(2) = 38 = T(1) + 8 .....(2) T(3) = 46 = T(2) + 8 .....(3) T(4) = 54 = T(3) + 8 .....(4) ......................................... T(n) = T(n-1) + 8 ..........(n)(1) + (2) + (3) + (4) + ... + (n) : T(1) + T(2) + T(3) + T(4) + ... + T(n) = 30 + T(1)+8 + T(2)+8 + T(3)+8 + ... +T(n-1)+8T(n) = 30 + 8(n-1) = 8n - 22 2014-10-08 05:19:30 補充： 修正 : T(n) = 30 + 8(n-1) = 8n + 22
其他解答:
請作答吧．．．．．．|||||General term = 30 + 8(n-1) = 30 - 8 + 8n = 8n + 22
maths
發問:
30,38,46,54的general term 係咩?
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最佳解答:記T(n)為general term(通項), 則T(1) = 30 .....................(1) T(2) = 38 = T(1) + 8 .....(2) T(3) = 46 = T(2) + 8 .....(3) T(4) = 54 = T(3) + 8 .....(4) ......................................... T(n) = T(n-1) + 8 ..........(n)(1) + (2) + (3) + (4) + ... + (n) : T(1) + T(2) + T(3) + T(4) + ... + T(n) = 30 + T(1)+8 + T(2)+8 + T(3)+8 + ... +T(n-1)+8T(n) = 30 + 8(n-1) = 8n - 22 2014-10-08 05:19:30 補充： 修正 : T(n) = 30 + 8(n-1) = 8n + 22
其他解答:
請作答吧．．．．．．|||||General term = 30 + 8(n-1) = 30 - 8 + 8n = 8n + 22
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