標題:
Applied math~ Vector!~~
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發問:
http://img532.imageshack.us/img532/2844/vectorz.png假設(i - 6j) 係A(7i - 14j) 係BAB = 6i - 8j我用左個方法:因P係constant, apply v^2 - u^2 = 2as(2 sqrt(7) )^2 = 2 |a| (10) (s = |AB| = 10).'. a = 1.4 (1)because P = mak(6i + j) = 0.5aa = 2k(6i + j)|a|^2 = 144k^2 + 4k^2 = 148k^2 ... 顯示更多 http://img532.imageshack.us/img532/2844/vectorz.png 假設(i - 6j) 係A (7i - 14j) 係B AB = 6i - 8j 我用左個方法: 因P係constant, apply v^2 - u^2 = 2as (2 sqrt(7) )^2 = 2 |a| (10) (s = |AB| = 10) .'. a = 1.4 (1) because P = ma k(6i + j) = 0.5a a = 2k(6i + j) |a|^2 = 144k^2 + 4k^2 = 148k^2 (2) From (1) and (2), k = 0.115079291 why it is wrong?? the correct k is 1/4
最佳解答:
=================================================== 圖片參考：http://img521.imageshack.us/img521/3827/41125916.png 2010-03-25 21:51:39 補充： http://img521.imageshack.us/img521/3827/41125916.png
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