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complex number(電路)
For the RLC circuit shown in figure Q9,the supply voltage is v=220arg0 .The resistance of the resistor R is 15-ohm,the reactance XL of the inductor L is 20-ohm and the reactance XC of the capacitor C is 8-ohm. ┌──R────C────L───┐ ││ ↑(I)│ ││... 顯示更多 For the RLC circuit shown in figure Q9,the supply voltage is v=220arg0 .The resistance of the resistor R is 15-ohm,the reactance XL of the inductor L is 20-ohm and the reactance XC of the capacitor C is 8-ohm. ┌──R────C────L───┐ ││ ↑(I)│ ││ ││ └───(V=220arg0)─────┘ Determine 1)the impedance Z of the circuit 2)the current I flowing in the circuit 3)the voltages across the resistor R,the inductor L and the capacitor C. 4)Sketch the voltages on the Argand diagram.
最佳解答:
1) Impedance = Resistance + Reactance. Inductor is positive reactance and capacitor is negative reactance. So impedance of circuit = 15 + 20j - 8j = 15 + 12j = 19.21 arg [arctan(12/15)] = 19.21 arg 38.66 2) Current = V/Z = 220 arg 0/19.21 arg 38.66 = 11.45 arg ( - 38.66) 3) Voltage across resistor = IR = 15 x 11.45 arg ( - 38.66) = 171.79 arg ( - 38.66) Voltage across inductor = IXL = 11.45 arg ( - 38.66) x 20 arg ( 90) = 229 arg 51.34 Voltage across capacitor = IXC = 11.45 arg ( - 38.66) x 8 arg(- 90) = 91.6 arg ( - 128.66) 4) Vr = 134.14 - 107.32j Vl = 143.06 + 178.82j Vc = - 57.22 - 71.53j Vr + Vl + Vc = 220 = supplied voltage.
其他解答:
complex number(電路)
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發問:For the RLC circuit shown in figure Q9,the supply voltage is v=220arg0 .The resistance of the resistor R is 15-ohm,the reactance XL of the inductor L is 20-ohm and the reactance XC of the capacitor C is 8-ohm. ┌──R────C────L───┐ ││ ↑(I)│ ││... 顯示更多 For the RLC circuit shown in figure Q9,the supply voltage is v=220arg0 .The resistance of the resistor R is 15-ohm,the reactance XL of the inductor L is 20-ohm and the reactance XC of the capacitor C is 8-ohm. ┌──R────C────L───┐ ││ ↑(I)│ ││ ││ └───(V=220arg0)─────┘ Determine 1)the impedance Z of the circuit 2)the current I flowing in the circuit 3)the voltages across the resistor R,the inductor L and the capacitor C. 4)Sketch the voltages on the Argand diagram.
最佳解答:
1) Impedance = Resistance + Reactance. Inductor is positive reactance and capacitor is negative reactance. So impedance of circuit = 15 + 20j - 8j = 15 + 12j = 19.21 arg [arctan(12/15)] = 19.21 arg 38.66 2) Current = V/Z = 220 arg 0/19.21 arg 38.66 = 11.45 arg ( - 38.66) 3) Voltage across resistor = IR = 15 x 11.45 arg ( - 38.66) = 171.79 arg ( - 38.66) Voltage across inductor = IXL = 11.45 arg ( - 38.66) x 20 arg ( 90) = 229 arg 51.34 Voltage across capacitor = IXC = 11.45 arg ( - 38.66) x 8 arg(- 90) = 91.6 arg ( - 128.66) 4) Vr = 134.14 - 107.32j Vl = 143.06 + 178.82j Vc = - 57.22 - 71.53j Vr + Vl + Vc = 220 = supplied voltage.
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