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F.2----4題數學題 1.Convert 2E1(16) into a denary number. 2.Convert 110110(2) into a denary numder. 3.Convert 37(10) into a binary number. 4.Convert 444(10) into a hexadecimal number. THZ
最佳解答:
1. Convert 2E1(16) into a denary number. 2E1(16) = 2 x 162 + 14 x 16 + 1 x 1 = 737(10) 2. Convert 110110(2) into a denary number. 110110(2) = 1 x 25 + 1 x 24 + 0 x 23 + 1 x 22 + 1x 2 + 0 x 1 = 54(10) 3. Convert 37(10) into a binary number. By division, the remainders arrange as 1, 0, 0, 1, 1 and 1. So 37(10) = 100101(2) 4. Convert 444(10) into a hexadecimal number. By division, the remainders arrange as 1, B and C. So 444(10) = 1BC(16)
其他解答:
1) 2E1 (16) = 737 (10) 2) 110110 (2) = 54 (10) 3) 37 (10) = 100101 (2) 4) 444 (10) = 1BC (16) 補充: denary number = 10 進制 binary number = 2 進制 hexadecimal number = 16 進制 () 內數字是代表?進制 例如: 444 (10) = 1BC (16) 即係10 進制既 444 = 16 進制既 1BC
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F.2----4題數學題發問:
F.2----4題數學題 1.Convert 2E1(16) into a denary number. 2.Convert 110110(2) into a denary numder. 3.Convert 37(10) into a binary number. 4.Convert 444(10) into a hexadecimal number. THZ
最佳解答:
1. Convert 2E1(16) into a denary number. 2E1(16) = 2 x 162 + 14 x 16 + 1 x 1 = 737(10) 2. Convert 110110(2) into a denary number. 110110(2) = 1 x 25 + 1 x 24 + 0 x 23 + 1 x 22 + 1x 2 + 0 x 1 = 54(10) 3. Convert 37(10) into a binary number. By division, the remainders arrange as 1, 0, 0, 1, 1 and 1. So 37(10) = 100101(2) 4. Convert 444(10) into a hexadecimal number. By division, the remainders arrange as 1, B and C. So 444(10) = 1BC(16)
其他解答:
1) 2E1 (16) = 737 (10) 2) 110110 (2) = 54 (10) 3) 37 (10) = 100101 (2) 4) 444 (10) = 1BC (16) 補充: denary number = 10 進制 binary number = 2 進制 hexadecimal number = 16 進制 () 內數字是代表?進制 例如: 444 (10) = 1BC (16) 即係10 進制既 444 = 16 進制既 1BC
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