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hkcee 2003 maths mc 42
發問:
In the figure, ABCD and PQRS are two rectangles of equal perimeter. If AB:BC =3:2 and PQ:QR = 4:3 ,then area of ABCD : are of PQRS =
最佳解答:
Let AB=3x and BC=2x ,PQ=4y and QR=3y ABCD and PQRS are two rectangles of equal perimeter 2(AB+BC)=2(PQ+QR) 3x+2x=4y+3y 5x=7y x/y=7/5 area of ABCD : area of PQRS =(AB)(BC):(PQ)(QR) =(3x)(2x):(4y)(3y) =6x^2:12y^2 =x^2:2y^2 =1:2(y/x)^2 =1:2(5/7)^2 =1:50/49 =49:50
其他解答:
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