標題:
數學問題 - Equation of Straight line - 40分!!!!!!
Find the equation of the circle that passes through the three points (0,0) , (3,-1) , (6,8), give the answer in the general form 佢俾左圓形 3 個既coordinate, 點樣搵番個general form?
最佳解答:
Let the equation of the circle C be x^2+y^2+Dx+Ey+F=0 (0,0) , (3,-1) , (6,8) lie on C. 0^2+0^2+D(0)+E(0)+F=0 F=0 3^2+(-1)^2+D(3)+E(-1)+F=0 3D-E+10=0 6D-2E+20=0 ----- (1) 6^2+8^2+D(6)+E(8)+F=0 6D+8E+100=0 ----- (2) (1)-(2) 6D-2E+20-6D-8E-100=0 -8E=80 E=-10 Substitute E=-10 into (1) 6D-2(-10)+20=0 6D=-40 D=-20/3 The equation of C is x^2+y^2-20/3x-10y=0 Hope that I can help you...^^ 2008-09-12 23:34:04 補充： Sorry!! Please read this one: (1)-(2) 6D-2E+20-6D-8E-100=0 -10E=80 E= -8 Substitute E= -8 into (1) 6D-2(-8)+20=0 6D= -36 D= -6 The equation of C is x^2+y^2-6x-8y=0
其他解答:
(0,0) , (3,-1) , (6,8)=8.8 100.785+45.46-17.59=?
數學問題 - Equation of Straight line - 40分!!!!!!
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發問:Find the equation of the circle that passes through the three points (0,0) , (3,-1) , (6,8), give the answer in the general form 佢俾左圓形 3 個既coordinate, 點樣搵番個general form?
最佳解答:
Let the equation of the circle C be x^2+y^2+Dx+Ey+F=0 (0,0) , (3,-1) , (6,8) lie on C. 0^2+0^2+D(0)+E(0)+F=0 F=0 3^2+(-1)^2+D(3)+E(-1)+F=0 3D-E+10=0 6D-2E+20=0 ----- (1) 6^2+8^2+D(6)+E(8)+F=0 6D+8E+100=0 ----- (2) (1)-(2) 6D-2E+20-6D-8E-100=0 -8E=80 E=-10 Substitute E=-10 into (1) 6D-2(-10)+20=0 6D=-40 D=-20/3 The equation of C is x^2+y^2-20/3x-10y=0 Hope that I can help you...^^ 2008-09-12 23:34:04 補充： Sorry!! Please read this one: (1)-(2) 6D-2E+20-6D-8E-100=0 -10E=80 E= -8 Substitute E= -8 into (1) 6D-2(-8)+20=0 6D= -36 D= -6 The equation of C is x^2+y^2-6x-8y=0
其他解答:
(0,0) , (3,-1) , (6,8)=8.8 100.785+45.46-17.59=?
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