標題:
超多數學功課問題？？？？？？？(20分)
發問:
有少許的步驟便足夠了。(當然要答案la！)41. (2y+1)+[(2y+1)+3]+[(2y+1)+5]42. (2y+2)+[(2y+2)+4] +[(2y+4)+6]43. (y+1)+[(3y+3)+3]+[(5y+5)+5]44. [(y)(y)+1]+[(y)(y)+3]+[(y)(y)+5]45. [(2)(y)(y)+2]+[(4)(y)(y)+4]+[(6)(y)(y)+6]46. [(2)(w)(y)+1]+[(2)(w)(y)+3] 47. [(3)(w)(w)(y)+3]+[(5)(w)(w)(y)+4]48. [(4)(w)(y)+1]+{[(4)(w)(y)+2]}49.... 顯示更多 有少許的步驟便足夠了。(當然要答案la！) 41. (2y+1)+[(2y+1)+3]+[(2y+1)+5] 42. (2y+2)+[(2y+2)+4] +[(2y+4)+6] 43. (y+1)+[(3y+3)+3]+[(5y+5)+5] 44. [(y)(y)+1]+[(y)(y)+3]+[(y)(y)+5] 45. [(2)(y)(y)+2]+[(4)(y)(y)+4]+[(6)(y)(y)+6] 46. [(2)(w)(y)+1]+[(2)(w)(y)+3] 47. [(3)(w)(w)(y)+3]+[(5)(w)(w)(y)+4] 48. [(4)(w)(y)+1]+{[(4)(w)(y)+2]} 49. [(5)(w)(w)(y)+3]+{[(6)(w)(w)(y)+7]+2} 50. (6y-2w+1)+[(3y+9w)+5] 更新: { 大過 [ [ 大過 ( 更新 2: 睇唔到的話，請用Microsoft Word放大來看。
41)(2y+1)+[(2y+1)+3]+[(2y+1)+5] =2y+2y+2y+1+1+1+3+5 =6y+11 42)(2y+2)+[(2y+2)+4]+[(2y+4)+6] =2y+2y+2y+2+2+4+4+6 =6y+18 43)(y+1)+[(3y+3)+3]+[(5y+5)+5] =y+3y+5y+1+3+3+5+5 =9y+17 44)[(y)(y)+1]+[(y)(y)+3]+[(y)(y)+5] =y^6+3+1+5 =y^6+9 45)[(2)(y)(y)+2]+[(4)(y)(y)+4]+[(6)(y)(y)+6] =2y^2+4y^2+6y^2+2+4+6 =12y^2+12 46)[(2)(w)(y)+1]+[(2)(w)(y)+3] =2wy+2wy+1+3 =4wy+4 47)[(3)(w)(w)(y)+3]+[(5)(w)(w)(y)+4] =3w^2y+5w^2y+3+4 =8w^2y+7 48)[(4)(w)(y)+1]+{[(4)(w)(y)+2]} =4wy+4wy+1+2 =8wy+3 49)[(5)(w)(w)(y)+3]+{[(6)(w)(w)(y)+7]+2} =5wwy+6wwy+3+7+2 =11wwy+12 50)(6y-2w+1)+[(3y+9w)+5] =6y+3y+9w-2w+1+5 =9y+7w+6
其他解答:
應該是這樣： 41.=(2y+1)(1+3+5) =8(2y+1) 42.=(2y+2)(1+4+2+6) =13(2y+2) 43.=(y+1)[3(y+1)+3][5(y+1)+5] =(y+1)(3+5)+7 =8(y+1)+7 44.=(y)(y)(1+3+5) =9(y)(y) 45.=2{[(y)(y)+1][2(y)(y)+2]+[3(y)(y)+1]} =2[(y)(y)+1](1+2+3) =12[(y)(y)+1] 46.=4[(2)(w)(y)] 47.=[(15)(w)(w)(y)]+7 48.=[(4)(w)(y)](1+2) =[(4)(w)(y)](3) 49.=(30)(w)(w)(y)+12 50.=[2(3y-w)+1]+[3(y+3w)+5]|||||41. (2y+1)+[(2y+1)+3]+[(2y+1)+5] =6y+11 42. (2y+2)+[(2y+2)+4] +[(2y+4)+6] =6y+18 43. (y+1)+[(3y+3)+3]+[(5y+5)+5] =9y+17 44. [(y)(y)+1]+[(y)(y)+3]+[(y)(y)+5] =3y^2+9 45. [(2)(y)(y)+2]+[(4)(y)(y)+4]+[(6)(y)(y)+6] =12y^2+12 46. [(2)(w)(y)+1]+[(2)(w)(y)+3] =4wy+4 47. [(3)(w)(w)(y)+3]+[(5)(w)(w)(y)+4] =8w^2y+7 48. [(4)(w)(y)+1]+{[(4)(w)(y)+2]} =8wy+3 49. [(5)(w)(w)(y)+3]+{[(6)(w)(w)(y)+7]+2} 50. (6y-2w+1)+[(3y+9w)+5] =9y+7w+6 2007-10-22 17:29:15 補充： 49.=11w^2y 12 2007-10-22 17:30:31 補充： 49.11w^2y 12 才正確 he! he!|||||41. (2y+1)+[(2y+1)+3]+[(2y+1)+5] =(2y+1)+(2y+1+3)+(2y+1+5) =2y+1+2y+1+3+2y+1+5 =6y+11 42. (2y+2)+[(2y+2)+4] +[(2y+4)+6] =2y+2+2y+2+4 +2y+4+6 =6y+18 43. (y+1)+[(3y+3)+3]+[(5y+5)+5] =y+1+3y+3+3+5y+5+5 =9y+17 44. [(y)(y)+1]+[(y)(y)+3]+[(y)(y)+5] =y^2+1+y^2+3+y^2+5 =y^2+9 45. [(2)(y)(y)+2]+[(4)(y)(y)+4]+[(6)(y)(y)+6] = 2y^2+2+4y^2+4+6y^2+6 =12y^2+12 46. [(2)(w)(y)+1]+[(2)(w)(y)+3] =2wy+1+2wy+3 =4wy+4 47. [(3)(w)(w)(y)+3]+[(5)(w)(w)(y)+4] =3w^2y+3+5w^2y+4 =8w^2y+7 48. [(4)(w)(y)+1]+{[(4)(w)(y)+2]} = 4wy+1+4wy+2 =8wy+3 49. [(5)(w)(w)(y)+3]+{[(6)(w)(w)(y)+7]+2} =5w^2y+3+6w^2y+7+2 =11w^2y+12 50. (6y-2w+1)+[(3y+9w)+5] = 6y-2w+1+3y+9w+5 =3y+7w+6
超多數學功課問題？？？？？？？(20分)
發問:
有少許的步驟便足夠了。(當然要答案la！)41. (2y+1)+[(2y+1)+3]+[(2y+1)+5]42. (2y+2)+[(2y+2)+4] +[(2y+4)+6]43. (y+1)+[(3y+3)+3]+[(5y+5)+5]44. [(y)(y)+1]+[(y)(y)+3]+[(y)(y)+5]45. [(2)(y)(y)+2]+[(4)(y)(y)+4]+[(6)(y)(y)+6]46. [(2)(w)(y)+1]+[(2)(w)(y)+3] 47. [(3)(w)(w)(y)+3]+[(5)(w)(w)(y)+4]48. [(4)(w)(y)+1]+{[(4)(w)(y)+2]}49.... 顯示更多 有少許的步驟便足夠了。(當然要答案la！) 41. (2y+1)+[(2y+1)+3]+[(2y+1)+5] 42. (2y+2)+[(2y+2)+4] +[(2y+4)+6] 43. (y+1)+[(3y+3)+3]+[(5y+5)+5] 44. [(y)(y)+1]+[(y)(y)+3]+[(y)(y)+5] 45. [(2)(y)(y)+2]+[(4)(y)(y)+4]+[(6)(y)(y)+6] 46. [(2)(w)(y)+1]+[(2)(w)(y)+3] 47. [(3)(w)(w)(y)+3]+[(5)(w)(w)(y)+4] 48. [(4)(w)(y)+1]+{[(4)(w)(y)+2]} 49. [(5)(w)(w)(y)+3]+{[(6)(w)(w)(y)+7]+2} 50. (6y-2w+1)+[(3y+9w)+5] 更新: { 大過 [ [ 大過 ( 更新 2: 睇唔到的話，請用Microsoft Word放大來看。
此文章來自奇摩知識+如有不便請留言告知
最佳解答:41)(2y+1)+[(2y+1)+3]+[(2y+1)+5] =2y+2y+2y+1+1+1+3+5 =6y+11 42)(2y+2)+[(2y+2)+4]+[(2y+4)+6] =2y+2y+2y+2+2+4+4+6 =6y+18 43)(y+1)+[(3y+3)+3]+[(5y+5)+5] =y+3y+5y+1+3+3+5+5 =9y+17 44)[(y)(y)+1]+[(y)(y)+3]+[(y)(y)+5] =y^6+3+1+5 =y^6+9 45)[(2)(y)(y)+2]+[(4)(y)(y)+4]+[(6)(y)(y)+6] =2y^2+4y^2+6y^2+2+4+6 =12y^2+12 46)[(2)(w)(y)+1]+[(2)(w)(y)+3] =2wy+2wy+1+3 =4wy+4 47)[(3)(w)(w)(y)+3]+[(5)(w)(w)(y)+4] =3w^2y+5w^2y+3+4 =8w^2y+7 48)[(4)(w)(y)+1]+{[(4)(w)(y)+2]} =4wy+4wy+1+2 =8wy+3 49)[(5)(w)(w)(y)+3]+{[(6)(w)(w)(y)+7]+2} =5wwy+6wwy+3+7+2 =11wwy+12 50)(6y-2w+1)+[(3y+9w)+5] =6y+3y+9w-2w+1+5 =9y+7w+6
其他解答:
應該是這樣： 41.=(2y+1)(1+3+5) =8(2y+1) 42.=(2y+2)(1+4+2+6) =13(2y+2) 43.=(y+1)[3(y+1)+3][5(y+1)+5] =(y+1)(3+5)+7 =8(y+1)+7 44.=(y)(y)(1+3+5) =9(y)(y) 45.=2{[(y)(y)+1][2(y)(y)+2]+[3(y)(y)+1]} =2[(y)(y)+1](1+2+3) =12[(y)(y)+1] 46.=4[(2)(w)(y)] 47.=[(15)(w)(w)(y)]+7 48.=[(4)(w)(y)](1+2) =[(4)(w)(y)](3) 49.=(30)(w)(w)(y)+12 50.=[2(3y-w)+1]+[3(y+3w)+5]|||||41. (2y+1)+[(2y+1)+3]+[(2y+1)+5] =6y+11 42. (2y+2)+[(2y+2)+4] +[(2y+4)+6] =6y+18 43. (y+1)+[(3y+3)+3]+[(5y+5)+5] =9y+17 44. [(y)(y)+1]+[(y)(y)+3]+[(y)(y)+5] =3y^2+9 45. [(2)(y)(y)+2]+[(4)(y)(y)+4]+[(6)(y)(y)+6] =12y^2+12 46. [(2)(w)(y)+1]+[(2)(w)(y)+3] =4wy+4 47. [(3)(w)(w)(y)+3]+[(5)(w)(w)(y)+4] =8w^2y+7 48. [(4)(w)(y)+1]+{[(4)(w)(y)+2]} =8wy+3 49. [(5)(w)(w)(y)+3]+{[(6)(w)(w)(y)+7]+2} 50. (6y-2w+1)+[(3y+9w)+5] =9y+7w+6 2007-10-22 17:29:15 補充： 49.=11w^2y 12 2007-10-22 17:30:31 補充： 49.11w^2y 12 才正確 he! he!|||||41. (2y+1)+[(2y+1)+3]+[(2y+1)+5] =(2y+1)+(2y+1+3)+(2y+1+5) =2y+1+2y+1+3+2y+1+5 =6y+11 42. (2y+2)+[(2y+2)+4] +[(2y+4)+6] =2y+2+2y+2+4 +2y+4+6 =6y+18 43. (y+1)+[(3y+3)+3]+[(5y+5)+5] =y+1+3y+3+3+5y+5+5 =9y+17 44. [(y)(y)+1]+[(y)(y)+3]+[(y)(y)+5] =y^2+1+y^2+3+y^2+5 =y^2+9 45. [(2)(y)(y)+2]+[(4)(y)(y)+4]+[(6)(y)(y)+6] = 2y^2+2+4y^2+4+6y^2+6 =12y^2+12 46. [(2)(w)(y)+1]+[(2)(w)(y)+3] =2wy+1+2wy+3 =4wy+4 47. [(3)(w)(w)(y)+3]+[(5)(w)(w)(y)+4] =3w^2y+3+5w^2y+4 =8w^2y+7 48. [(4)(w)(y)+1]+{[(4)(w)(y)+2]} = 4wy+1+4wy+2 =8wy+3 49. [(5)(w)(w)(y)+3]+{[(6)(w)(w)(y)+7]+2} =5w^2y+3+6w^2y+7+2 =11w^2y+12 50. (6y-2w+1)+[(3y+9w)+5] = 6y-2w+1+3y+9w+5 =3y+7w+6
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