close
標題:

Maths 的問題 fast!!!!

發問:

aa.jpg

 

此文章來自奇摩知識+如有不便請留言告知

Factorize 有式!!!!!''=2次方,'''=31, 2ab-14bc+18bd2, 2ax-20ax'''-4a"x"3, -8a'''b''-12a''b''+4ab4, 5x(x-4)+2(4-x)5, 5(3m-n)''-(n-3m)6, 4xy-3y+3z-4xz7, 15bx-3b+5ax-a8, 6mb-4ma-6na+9nb9,... 顯示更多 Factorize 有式!!!!! ''=2次方,'''=3 1, 2ab-14bc+18bd 2, 2ax-20ax'''-4a"x" 3, -8a'''b''-12a''b''+4ab 4, 5x(x-4)+2(4-x) 5, 5(3m-n)''-(n-3m) 6, 4xy-3y+3z-4xz 7, 15bx-3b+5ax-a 8, 6mb-4ma-6na+9nb 9, uv-u-v''+v 10, cd''-c''d-c+d 11, 8m''-8m+2 12, 27y''+18y+3 13, a''b''-2abc+c'' 14, 32+48n+18n'' 15, 2a''-28ab+98b'' 16, 80y''+40ys+5s'' 17,3x''-18xy+27y'' 18, x''+4(x+1) 19, x(x-10)+25 20, 64x''-9y'' 21, 49-81y'' 22, (x+1)''-9 23, 49-(2x-1)'' 24, 16m''n''-(-3)'' 更新: sorry '''=3次方 not 3

最佳解答:

1, 2ab-14bc+18bd = 2b (a-7c+9d) 2, 2ax-20ax'''-4a"x" = 2ax (1 – 20 x"- 2ax) = 2ax [1 -2x (10x-a)] 3, -8a'''b''-12a''b''+4ab = -4ab (2a''b+3ab-1) 4, 5x(x-4)+2(4-x) = 5x (x-4) – 2 (x-4) = (5x-2) (x-4) 5, 5(3m-n)''-(n-3m) = 5 (3m-n) '' + (3m-n) = (3m-n) [5(3m-n) +1] 6, 4xy-3y+3z-4xz = y(4x-3) – z(4x-3) = (y-z) (4x-3) 7, 15bx-3b+5ax-a = 3b (5x-1) + a (5x-1) = (3b-a) (5x-1) 8, 6mb-4ma-6na+9nb = 2m (3b-2a) + 3n (3b-2a) = (2m+3n) (3b-2a) 9, uv-u-v''+v = u (v-1) – v (v-1) = (u-v) (v-1) 10, cd''-c''d-c+d = cd (d-c) + (d-c) = (cd+1) (d-c) 11, 8m''-8m+2 = 2 (4m''-4m +1) = 2 (2m -1) '' 12, 27y''+18y+3 = 3 (9y''+6y+1) = 3 (3y+1) '' 13, a''b''-2abc+c'' = (ab –c) '' 14, 32+48n+18n'' = 2 (9n'' + 24n +16) = 2 (3n+4) '' 15, 2a''-28ab+98b'' = 2 (a''-14ab +48b'') = 2 (a-8) (a-6) 16, 80y''+40ys+5s'' = 5 (16y''+8ys +s'') = 5 (4y+s) '' 17,3x''-18xy+27y'' = 3 (x'' -6xy +9y'') = 3 (x-3y) '' 18, x''+4(x+1) = x''+ 4x +4 = (x+2) '' 19, x(x-10)+25 = x''-10x +25 = (x-5) '' 20, 64x''-9y'' = (8x-3y) (8x+3y) 21, 49-81y'' = (7 +9y) (7-9y) 22, (x+1)''-9 = [(x+1) + 3][(x+1)-3] = (x+4) (x-2) 23, 49-(2x-1)'' = [7-(2x-1)][7+(2x-1)] = (8-2x) (6+2x) = 4 (4-x) (3+x) 24, 16m''n''-(-3)'' = 16m''n''- 9 = (4mn+3) (4mn-3)

其他解答:
arrow
arrow

    ohe09nz81r 發表在 痞客邦 留言(0) 人氣()