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標題:
Math Factoring Perfect-Square
發問:
Factoring Perfect-Square Trinomials and the Difference of two squares.公式:A^2+2AB+B^2= (A+B)^2A^2-2AB+B^2= (A-B)^2F^2-L^2= (F+L) (F-L)請數學高手解答和列出步驟.......感謝!Factor.1) x^2+10x+252) -z^2+2z-13) x^2-94) 9y^2+16-24y5) 25a^2 + 20ab +4b^26) 49t^2-121y^27) x^2y^2-4008) c^4-2569) ... 顯示更多 Factoring Perfect-Square Trinomials and the Difference of two squares. 公式: A^2+2AB+B^2= (A+B)^2 A^2-2AB+B^2= (A-B)^2 F^2-L^2= (F+L) (F-L) 請數學高手解答和列出步驟.......感謝! Factor. 1) x^2+10x+25 2) -z^2+2z-1 3) x^2-9 4) 9y^2+16-24y 5) 25a^2 + 20ab +4b^2 6) 49t^2-121y^2 7) x^2y^2-400 8) c^4-256 9) 8at^2-32a 10) h^2+36
最佳解答:
1) x2 + 10x + 25 = x2 + 2(5)x + 52 = (x + 5)2 2) -z2 + 2z - 1 = -(z2 - 2z + 1) = -(z - 1)2 3) x2 - 9 = x2 - 32 = (x + 3)(x - 3) 4) 9y2 + 16 - 24y = 9y2 - 24y + 16 = (3y)2 - 2(3y)(4) + 42 = (3y - 4)2 5) 25a2 + 20ab + 4b2 = (5a)2 + 2(5a)(2b) + (2b)2 = (5a + 2b)2 6) 49t2 - 121y2 = (7t)2 - (11y)2 = (7t + 11y)(7t - 11y) 7) x2y2 - 400 = (xy)2 - 202 = (xy + 20)(xy - 20) 8) c? - 256 = (c2)2 - 162 = (c2 + 16)(c2 - 16) = (c2 + 16)(c2 - 42) = (c2 + 16)(c + 4)(c - 4) 9) 8at2 - 32a = 8a(t2 - 4) = 8a(t2 - 22) = 8a(t + 2)(t - 2) 10) h2 + 36 cannot be factorized over real numbers. If the question is h2 - 36, then it is h2 - 62 = (h + 6)(h - 6)
其他解答:
Math Factoring Perfect-Square
發問:
Factoring Perfect-Square Trinomials and the Difference of two squares.公式:A^2+2AB+B^2= (A+B)^2A^2-2AB+B^2= (A-B)^2F^2-L^2= (F+L) (F-L)請數學高手解答和列出步驟.......感謝!Factor.1) x^2+10x+252) -z^2+2z-13) x^2-94) 9y^2+16-24y5) 25a^2 + 20ab +4b^26) 49t^2-121y^27) x^2y^2-4008) c^4-2569) ... 顯示更多 Factoring Perfect-Square Trinomials and the Difference of two squares. 公式: A^2+2AB+B^2= (A+B)^2 A^2-2AB+B^2= (A-B)^2 F^2-L^2= (F+L) (F-L) 請數學高手解答和列出步驟.......感謝! Factor. 1) x^2+10x+25 2) -z^2+2z-1 3) x^2-9 4) 9y^2+16-24y 5) 25a^2 + 20ab +4b^2 6) 49t^2-121y^2 7) x^2y^2-400 8) c^4-256 9) 8at^2-32a 10) h^2+36
最佳解答:
1) x2 + 10x + 25 = x2 + 2(5)x + 52 = (x + 5)2 2) -z2 + 2z - 1 = -(z2 - 2z + 1) = -(z - 1)2 3) x2 - 9 = x2 - 32 = (x + 3)(x - 3) 4) 9y2 + 16 - 24y = 9y2 - 24y + 16 = (3y)2 - 2(3y)(4) + 42 = (3y - 4)2 5) 25a2 + 20ab + 4b2 = (5a)2 + 2(5a)(2b) + (2b)2 = (5a + 2b)2 6) 49t2 - 121y2 = (7t)2 - (11y)2 = (7t + 11y)(7t - 11y) 7) x2y2 - 400 = (xy)2 - 202 = (xy + 20)(xy - 20) 8) c? - 256 = (c2)2 - 162 = (c2 + 16)(c2 - 16) = (c2 + 16)(c2 - 42) = (c2 + 16)(c + 4)(c - 4) 9) 8at2 - 32a = 8a(t2 - 4) = 8a(t2 - 22) = 8a(t + 2)(t - 2) 10) h2 + 36 cannot be factorized over real numbers. If the question is h2 - 36, then it is h2 - 62 = (h + 6)(h - 6)
其他解答:
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