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Equilibrium Constant
發問:
Kc=61 for the reaction N2(g) + 3H2(g) → 2NH3(g) at a certain temperature. Suppose it was found that an equilibrium mixture of these gases contained 0.3284 M NH3 and 0.017730 M N2. What is the concentration of H2 in the mixture?The answer is 0.463720087095, please show your solution clearly and steps by... 顯示更多 Kc=61 for the reaction N2(g) + 3H2(g) → 2NH3(g) at a certain temperature. Suppose it was found that an equilibrium mixture of these gases contained 0.3284 M NH3 and 0.017730 M N2. What is the concentration of H2 in the mixture? The answer is 0.463720087095, please show your solution clearly and steps by steps. Thank you very much~
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其他解答:
Equilibrium Constant
發問:
Kc=61 for the reaction N2(g) + 3H2(g) → 2NH3(g) at a certain temperature. Suppose it was found that an equilibrium mixture of these gases contained 0.3284 M NH3 and 0.017730 M N2. What is the concentration of H2 in the mixture?The answer is 0.463720087095, please show your solution clearly and steps by... 顯示更多 Kc=61 for the reaction N2(g) + 3H2(g) → 2NH3(g) at a certain temperature. Suppose it was found that an equilibrium mixture of these gases contained 0.3284 M NH3 and 0.017730 M N2. What is the concentration of H2 in the mixture? The answer is 0.463720087095, please show your solution clearly and steps by steps. Thank you very much~
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Kc=61 for the reaction N2(g) + 3H2(g) → 2NH3(g) at a certain temperature. Suppose it was found that an equilibrium mixture of these gases contained 0.3284 M NH3 and 0.017730 M N2. What is the concentration of H2 in the mixture? N2(g) + 3H2(g) ≒ 2NH3(g) At equilibrium: [NH3] = 0.3284 mol dm-3 [N2] = 0.017730 mol dm-3 Kc = [NH3]2/([N2]?[H2]3) 61 = (0.3284)2/(0.017730)[H2]3) Concentration of H2 in the equilibrium mixture, [H2] = [(0.3284)2/(0.017730)(61)]1/3 = 0.4637 mol dm-3 (to 4 sig. fig.)其他解答:
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