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一元一次方程

發問:

請問如何做,我不會做 1. 7A= - 56 2. 5b+3=-12 3.16=8+0.4t 求解答過程，謝謝 請今天解答我

最佳解答:

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此文章來自奇摩知識+如有不便請留言告知

1, 7a = -56 a = -56 / 7 = -8 2, 5b +3 = -12 5b = -12 - 3 = -15 b = -15 / 5 = -3 3, 16 = 8 +0.4t 0.4t = 16 - 8 = 8 t = 8 / 0.4 = 20

其他解答:

1. 7A= - 56 A=-56/7 A=-8 2. 5b+3=-12 5b+3-3=-12-3 5b=-15 b=-15/5=-3 3.16=8+0.4t 0.4t = 16 - 8 = 8 t = 8 / 0.4 = 20|||||1.7a=-56 7a/-1 =-56/-1 -7a=56 -7a/7=56/7 -a=8 -a/-1=8/-1 a=-8 2.5b+3=12 5b+3-3=12-3 5b/5=9/5 b=1.8 3.16=8+0.4t 16-8=8+0.4t-8 8/0.4=0.4t/0.4 20=t t=20|||||1. 7A=56 7A /7 =56/7 A=8 2. 5b+3=12 5b+3-3=12-3 5b/5=9/5 b=1.8 3. 16=8+0.4t 16-8=8+0.4t-8 8=0.4t 8/0.4=0.4t/0.4 0.05=t t=0.05 2007-02-26 18:48:02 補充： 1. 7A=567A /7 =56/7A=82. 5b 3=125b 3-3=12-35b/5=9/5b=1.83.16=8 0.4t16-8=8 0.4t-88=0.4t8/0.4=0.4t/0.40.05=tt=0.05 2007-02-26 18:48:04 補充： 1. 7A=567A /7 =56/7A=82. 5b 3=125b 3-3=12-35b/5=9/5b=1.83.16=8 0.4t16-8=8 0.4t-88=0.4t8/0.4=0.4t/0.40.05=tt=0.05|||||1.7A= -56 A= -56/7 A= -8 2.5b+3= -12 5b= -12-3 b= -15/5 b= -5 3.16=8+0.4t 16-8=0.4t 8/0.4=t 3.2=t t=3.2
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