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F.1 Maths (Algebraic) 20點!!

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要列式.20點.Fast!!!>_<2.Three times a number is ten more than half the sum of 15 and the number.Find the number.3.Susan is six years older than Janet.Twelve years ago,the age of anet was half the age of Susan.Find their present ages.4.There are 4 $10 coins and y $2 conis inside a bag.If the value of the... 顯示更多 要列式.20點.Fast!!!>_< 2.Three times a number is ten more than half the sum of 15 and the number.Find the number. 3.Susan is six years older than Janet.Twelve years ago,the age of anet was half the age of Susan.Find their present ages. 4.There are 4 $10 coins and y $2 conis inside a bag.If the value of the conis in the bag is $58,find y. 5.David bought 11 ball-points pens for $12 each and y pencils for $7 each.If David paid $237 in total,find y. 6.Kiki's father is now 46 years old.8 years later,Kiki's father will be 2 times as old as her.Find the age of kiki now. 7.A wire with length 105 cm is cut into two.They are bent to form an equilateral triangle with lengths y cm and a square with lenghts 3y cm.Find the area of the square. Thx Thx Thx .! 更新: thx ka ho , i will choose yours be the best ans thx for help

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2.Three times a number is ten more than half the sum of 15 and the number.Find the number. let x be the number, 3x-(15+x)/2=10 6x-15+x =20 7x=35 x=5 3.Susan is six years older than Janet.Twelve years ago,the age of Janet was half the age of Susan.Find their present ages. let x be hte age of janet, then susan's age is (x+6) 2(x-12)=(x+6)-12 2x-24=x-6 x=18 susan is 24 and janet is 18 4.There are 4 $10 coins and y $2 conis inside a bag.If the value of the conis in the bag is $58,find y. 4x 10 + 2y =58 2y=58-40 y=9 5.David bought 11 ball-points pens for $12 each and y pencils for $7 each.If David paid $237 in total,find y. 11x 12 + 7y =237 7y =105 y =15 6.Kiki's father is now 46 years old.8 years later,Kiki's father will be 2 times as old as her.Find the age of kiki now. let x be the age of kiki 46+8=2(x+8) 54= 2x+16 x=19 7.A wire with length 105 cm is cut into two.They are bent to form an equilateral triangle with lengths y cm and a square with lenghts 3y cm.Find the area of the square. 3(y) +3y(4) =105 15y=105 y=7 then the length of the square =3x 7 =21 the area =21x 21 =441 2011-02-10 17:19:09 補充: sorry question 2 is wrong here is the correct one 2.Three times a number is ten more than half the sum of 15 and the number.Find the number. let x be the number, 3x-(15+x)/2=10 6x-15-x =20 5x=35 x=7

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