標題:

Chemistry question help!

發問:

What is the solubility of AgCl in moles per liter in a 0.020M MgCl2 solution? Ksp of AgCl = 1.56 x 10^ - 10 Show work please. Thank you.

最佳解答:

Each mol of MgCl2 gives 2 mol of Cl-. [Cl-]o = (0.02 M) x 2 = 0.04 M AgCl(s) ≒ Ag+(aq) + Cl-(aq) At equilibrium: [Ag+] = y M [Cl-] ≈ 0.04 M, because Ksp[AgCl(s)] is very small. Ksp = 0.04y = 1.56 x 10-10 y = 3.9 x 10-9 The solubility of AgCl is 3.9 x 10-9 mol dm-3. =

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