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Card games

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draw five cards from a standard deck and get a) four aces b) three aces and two jacks c) three aces and a pair 更新: why multiplying 10?

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最佳解答:

Say the probability for incedent E to occur as P(E). P(4 Aces)=4/52*3/51*2/50*1/49*5=1/54145=0.001847%(4 sig. fig.) P(3 Aces + 2 Jacks)=4/52*3/51*2/50*4/49*3/48*10=1/108290=0.0009234%(4 sig. fig.) P(3 Aces + Pair)=4/52*3/51*2/50*48/49*3/48*10=6/54145=0.01108%(4 sig. fig.)

其他解答:

why multiplying 10? Think about when two jacks and three aces are filled into 5 boxes, how many arrangements can there be. J J A A A J A J A A J A A J A J A A A J A J J A A A J A J A A J A A J A A J J A A A J A J A A A J J or by binomial distribution, 5C2 = 10

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