標題:
F.5 MATHS -probabilities
發問:
1. Two cards are randomly drawn from a pack of 52 playing cards (without jokers) without replacement. Find the probabilities of the following events happening. (a) The two cards are of the same unit (b) The two cards are of different suits. (c) There is at least one face card. (A face card means K,Q,J)
最佳解答:
- 點睇上昇星座-下表中,邊個係代表我上昇星座,有冇人識睇,講比我知呀-@1@
- 1. 某等差數列的第2項是-3,公差是4。求該數列的第8項。 2.某等差數列的首項是54,第9項是32。求該數列的公差。 3.某等差數列的第6項是3,第10項是47。求該數列的公差。 4.已知x,2x+1,2x+11,...是等差數列,求x的值。-
- Time expressions
- 點睇上昇星座-下表中,邊個係代表我上昇星座,有冇人識睇,講比我知呀-@1@
- 1. 某等差數列的第2項是-3,公差是4。求該數列的第8項。 2.某等差數列的首項是54,第9項是32。求該數列的公差。 3.某等差數列的第6項是3,第10項是47。求該數列的公差。 4.已知x,2x+1,2x+11,...是等差數列,求x的值。-
- Time expressions
此文章來自奇摩知識+如有不便請留言告知
a)P(The two cards are of the same unit)= P(Any 1st drawn card) * P(Any one of 3 other the same unit with the 1st card.)= (52/52) (3/51)= 3/51Alternatively :(13C1) (4C2) / 52C2= 3/51 b)P(The two cards are of different suits.)= P(Any 1st drawn card) * P(Any one of 13*3=39 other different suits cards.)= (52/52) * (39/51)= 39/51Alternatively :P(The two cards are of different suits.)= 1 - P(two cards with the same suit.)= 1 - (52/52)(12/51)= 39/51 c)P(at least one face card.)= 1 - P(two non-face cards)= 1 - (52 - 3*4) / 52](52 - 3*4 - 1) / 51= 1 - (40/52)(39/51) = 1 - (10/13)(13/17)= 21/51 2011-02-03 23:29:57 補充: a) Answer 3/51 = 1/17 b) Answer 39/51 = 13/17 c) Answer 21/51 = 7/17
其他解答: