標題:
A question about equilibrium
發問:
A particular reaction has a value of Kp=2.44 atm at 1000 K and 3.74 atm at 1200K. Find out the enthalpy change of this reaction.
ln K = ln A - ( ΔH / RT ) At 1000K, ln ( 2.44 ) = ln A - ( ΔH / 8.31 x 1000 ) --- ( 1 ) At 1200K, ln ( 3.74 ) = ln A - ( ΔH / 8.31 x 1200 ) --- ( 2 ) Combining ( 1 ) & ( 2 ), ln ( 2.44 ) + ( ΔH / 8310 ) = ln ( 3.74 ) + ( ΔH / 9972 ) ΔH = 21295 J / mol = + 21.3 kJ / mol
其他解答:
A question about equilibrium
發問:
A particular reaction has a value of Kp=2.44 atm at 1000 K and 3.74 atm at 1200K. Find out the enthalpy change of this reaction.
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最佳解答:ln K = ln A - ( ΔH / RT ) At 1000K, ln ( 2.44 ) = ln A - ( ΔH / 8.31 x 1000 ) --- ( 1 ) At 1200K, ln ( 3.74 ) = ln A - ( ΔH / 8.31 x 1200 ) --- ( 2 ) Combining ( 1 ) & ( 2 ), ln ( 2.44 ) + ( ΔH / 8310 ) = ln ( 3.74 ) + ( ΔH / 9972 ) ΔH = 21295 J / mol = + 21.3 kJ / mol
其他解答:
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