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急!F.2 Maths Challenge Question

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1) Uncle Luk has x lots of Stock A and y lots of Stock B. A lot of Stock A consists of 1000 shares and each share is currently $71. A lot of Stock B consists of 400 shares and each share is currently $85.(a) If he has a total of 70 lots of shares, find an equation connecting x and y.(b) Given that the total... 顯示更多 1) Uncle Luk has x lots of Stock A and y lots of Stock B. A lot of Stock A consists of 1000 shares and each share is currently $71. A lot of Stock B consists of 400 shares and each share is currently $85. (a) If he has a total of 70 lots of shares, find an equation connecting x and y. (b) Given that the total value of his shares is $3120000. (i) Find another equation connecting x and y. (ii) How many shares of Stock A and Stock B does he have? (c) Three days later, the prices of each share of Stock A has increased by 10% whilst Stock B has decreased by 20%. Uncle Luk then sells m lots of Stock A and buys n lots of Stock B. Finally, he has a total of 58 lots of shres and $4800 cash on hand, how many shares of Stock A and Stock B does he have? 應該同d simultaneous equations and linear equations with 2 unknowns 有關,因為我依家教緊。 *最好個answer有埋expression

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(a) x + y = 70 -- (1) (b)i) (71*1000)x + (85*400)y = 3120000 71000x + 34000y = 3120000 -- (2) ii) From (1) y = 70 - x -- (3) Sub (3) into (2) 71000x + 34000( 70-x ) = 3120000 71000x + 2380000 - 34000x = 3120000 37000x = 740000 x = 20 ∴y = 50 (70 - 20) (c) 我剩係做到個頭 因為唔明點解賣左咁多箱都得$4800 1箱都成幾萬蚊 The prices of each share of Stock A = (1.1)(71)(1000) = 78100 The prices of each share of Stock B = (0.8)(85)(400) = 27200 m + n = 70 - 58 m + n = 12 -- (4)

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