標題:
發問:
how to do it?................GIVE YOUR STEP..... 圖片參考：http://i795.photobucket.com/albums/yy231/qwert007008/004.jpg
最佳解答:
(a) In △FBD, E is the mid-point of FD. GE//BD FG = GB = 5 cm (Mid-point theorem) (b) In △AGE, C is the mid-point of AE. BC//GE AB = BG = 5 cm (Mid-point theorem) (c) In rt∠△FGE, FE2 = FG2 + GE2 132 = 52 + GE2 GE2 = 169 – 25 = 144 GE = 12 cm In △AGE, BC = GE / 2 = 12 / 2 cm = 6 cm In △FBD, GE = BD / 2 BD = 2 GE = 2 X 12 cm = 24 cm CD = BD – BC = 24 cm – 6 cm = 18 cm (d) In rt∠△ABC, AC2 = AB2 + BC2 AC2 = 52 + 62 = 25 + 36 = 61 AC = √61 cm = 7.81 cm ( correct to 2 decimal places )
其他解答:
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1Q (Intercept theorem)發問:
how to do it?................GIVE YOUR STEP..... 圖片參考：http://i795.photobucket.com/albums/yy231/qwert007008/004.jpg
最佳解答:
(a) In △FBD, E is the mid-point of FD. GE//BD FG = GB = 5 cm (Mid-point theorem) (b) In △AGE, C is the mid-point of AE. BC//GE AB = BG = 5 cm (Mid-point theorem) (c) In rt∠△FGE, FE2 = FG2 + GE2 132 = 52 + GE2 GE2 = 169 – 25 = 144 GE = 12 cm In △AGE, BC = GE / 2 = 12 / 2 cm = 6 cm In △FBD, GE = BD / 2 BD = 2 GE = 2 X 12 cm = 24 cm CD = BD – BC = 24 cm – 6 cm = 18 cm (d) In rt∠△ABC, AC2 = AB2 + BC2 AC2 = 52 + 62 = 25 + 36 = 61 AC = √61 cm = 7.81 cm ( correct to 2 decimal places )
其他解答:
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