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標題:

問數學題~!!!!!!!!!!!!!!!!!!!!10!!!!!!!!!

發問:

find the unkowns in the following 請寫清楚ed(int,alt,corr) http://i137.photobucket.com/albums/q209/ling8383/math2-1.jpg

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• 我想做兼職，最想就係pizza hut
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• where can buy 日本榭脂黏土-

 

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最佳解答:

Q1 k = 41 ( alt. angles, CD//AB ) Angle EGR = 56 ( adj. angles on st. line ) Therefore m = 56 ( corr. angles, CD//AB ) Q2 Construct a line through R which is parallel to QP and TS, and denoted as AB Angle QRA = 56 ( alt. angles, QP//AB ) Angle TRA = 30 ( alt. angles, TS//AB ) Therefore x = 56 + 30 = 86 Q3 Angle CBY = 62 ( corr. angles, CB//ZY ) Therefore Z = 180 - 75 - 62 ( adj. angles on st. line ) Z = 43 y = 75 ( corr. angles, AB//XY )

其他解答:

1. k=41 (alt angles) m=180-124=56 (corr angles sum of angles at the straight line=180) 2. angle TSR = 56 (alt angles) x=30+56=86 (ext angle of triangle) 3. y=75 (corr angles) angle CBY=62 (corr angles) z=180-75-62 =43 (sum of angles at the straight line=180)|||||10. k=41 m=56 11. x=86 12. z=43 y=75|||||圖片參考：http://i137.photobucket.com/albums/q209/ling8383/math2-1.jpg 10) k = 41(alt angle,AB // CD) m = AGR(corr . angle , AB // CD) m = 180 - 124(adj angle on st line) m = 56 11) let RK // PQ // ST QRK = 56(alt angle,RK//PQ) TRK = 30(alt angle,ST//RK) x = 56 + 30 x = 86 12) y = 75(corr.angle,AB//XY) CBY = 62(corr.angle,BC//YZ) z = 180 - 75 - 62(adj angle on the st line) = 43|||||唔知..............................................................