標題:
F6 AL Chem: Electronic Structure of Atoms
發問:
Given that the first four lines in the visible region of the emission spectrum of hydrogen. (Given: h= 6.62 x 10^-34 Js, L = 6.02 x 10^23, c = 3 x 10^8 m/s)a) What is the given name to the above series of lines? ( Sorry! I cannot show the graph here!)b) Calculate the frequency of the violet line in the... 顯示更多 Given that the first four lines in the visible region of the emission spectrum of hydrogen. (Given: h= 6.62 x 10^-34 Js, L = 6.02 x 10^23, c = 3 x 10^8 m/s) a) What is the given name to the above series of lines? ( Sorry! I cannot show the graph here!) b) Calculate the frequency of the violet line in the spectrum if that of the red line is 4.572 x 10^14 Hz.
最佳解答:
(a) Balmer Series (b) With reference to the formula of the Balmer series below: 圖片參考：http://upload.wikimedia.org/math/5/a/0/5a05645dc256a0aca0ab1c9cf97b6525.png where RH is the Rydberg constant, we have: For the first line, i.e. the red line, n = 3 For the fourth line, i.e. the violet line, n = 6 So, comparing their ratio of wavelength: Wavelength (violet) : Wavelength (red) = [(1/22) - (1/32)] : [(1/22) - (1/62)] = 5 : 8 Hence, their frequencies are in the ratio of: Freq (violet) : Freq (red) = 8 : 5 And therefore, the frequency of the violet line in the spectrum is: (8/5) x 4.572 x 1014 = 7.315 x 1014 Hz
F6 AL Chem: Electronic Structure of Atoms
發問:
Given that the first four lines in the visible region of the emission spectrum of hydrogen. (Given: h= 6.62 x 10^-34 Js, L = 6.02 x 10^23, c = 3 x 10^8 m/s)a) What is the given name to the above series of lines? ( Sorry! I cannot show the graph here!)b) Calculate the frequency of the violet line in the... 顯示更多 Given that the first four lines in the visible region of the emission spectrum of hydrogen. (Given: h= 6.62 x 10^-34 Js, L = 6.02 x 10^23, c = 3 x 10^8 m/s) a) What is the given name to the above series of lines? ( Sorry! I cannot show the graph here!) b) Calculate the frequency of the violet line in the spectrum if that of the red line is 4.572 x 10^14 Hz.
最佳解答:
(a) Balmer Series (b) With reference to the formula of the Balmer series below: 圖片參考：http://upload.wikimedia.org/math/5/a/0/5a05645dc256a0aca0ab1c9cf97b6525.png where RH is the Rydberg constant, we have: For the first line, i.e. the red line, n = 3 For the fourth line, i.e. the violet line, n = 6 So, comparing their ratio of wavelength: Wavelength (violet) : Wavelength (red) = [(1/22) - (1/32)] : [(1/22) - (1/62)] = 5 : 8 Hence, their frequencies are in the ratio of: Freq (violet) : Freq (red) = 8 : 5 And therefore, the frequency of the violet line in the spectrum is: (8/5) x 4.572 x 1014 = 7.315 x 1014 Hz
此文章來自奇摩知識+如有不便請留言告知
其他解答:
文章標籤
全站熱搜
留言列表
