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標題:
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發問:
Question: a and b are the roots of the equation 〖10x〗^2-19x-56=0. form a quadratic equation in x whose roots are a+3 and b+3. Please answer it, thanks.
最佳解答:
(10x)2 - 19x - 56 = 0 100x2 - 19x - 56 = 0 a and b are the roots. Sum of the roots: a + b = 19/100 Product of the roots: ab = -56/100 (a + 3) + (b + 3) = (a + b) + 6 = (19/100) + 6 = 619/100 (a + 3)(b + 3) = ab + 3a + 3b + 9 = ab + 3(a + b) + 9 = (-56/100) + 3(19/100) + 9 = 901/100 The required quadratic equation : x2 - (619/100)x + (901/100) = 0 100x2 - 619x + 901 = 0
其他解答:
Please slove the questions.
發問:
Question: a and b are the roots of the equation 〖10x〗^2-19x-56=0. form a quadratic equation in x whose roots are a+3 and b+3. Please answer it, thanks.
最佳解答:
(10x)2 - 19x - 56 = 0 100x2 - 19x - 56 = 0 a and b are the roots. Sum of the roots: a + b = 19/100 Product of the roots: ab = -56/100 (a + 3) + (b + 3) = (a + b) + 6 = (19/100) + 6 = 619/100 (a + 3)(b + 3) = ab + 3a + 3b + 9 = ab + 3(a + b) + 9 = (-56/100) + 3(19/100) + 9 = 901/100 The required quadratic equation : x2 - (619/100)x + (901/100) = 0 100x2 - 619x + 901 = 0
其他解答:
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