標題:
maths factorization f.3
1a) 9r2-(3r-4s)2 b) c2(c+2)-c-2 2a) (x+2)2-(x+2)(y-3)-6(y-3)2 b) 3(x+7)2+(x+7)(x-6)-14(x-6)2 3a) (k+1)2-(k+1)-56 b) (2x-3)2+10x-15
最佳解答:
1a)9r2-(3r-4s)2 =(3r)2-(3r-4s)2 =(3r+3r-4s)(3r-3r+4s) =(6r-4s)(4s) =8s(3r-2s)b)c2(c+2)-c-2 =c2(c+2)-(c+2) =(c2-1)(c+2) =(c+1)(c-1)(c+2)2a) (x+2)2-(x+2)(y-3)-6(y-3)2 let(x+2)be a,(y-3) be b =a2-ab-6b2 =(a-3b)(a+2b) =(x+2-3y+9)(x+2+2y-6) =(x-3y+11)(x-4+2y)b) 3(x+7)2+(x+7)(x-6)-14(x-6)2 let(x+7)be a,(x-6) be b =3a2+ab-14b2 =(3a+7b)(a-2b) =(3x+21+7x-42)(x+7-2x+12) =(10x-21)(19-x)3a) (k+1)2-(k+1)-56 =a2-a-56 =(a-8)(a+7) =(k-7)(k+8)b) (2x-3)2+10x-15 =4x2-12x+9+10x-15 =4x2-2x-6 =(2x-3)(2x+2) =2(2x-3)(x+1)
其他解答:
maths factorization f.3
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發問:1a) 9r2-(3r-4s)2 b) c2(c+2)-c-2 2a) (x+2)2-(x+2)(y-3)-6(y-3)2 b) 3(x+7)2+(x+7)(x-6)-14(x-6)2 3a) (k+1)2-(k+1)-56 b) (2x-3)2+10x-15
最佳解答:
1a)9r2-(3r-4s)2 =(3r)2-(3r-4s)2 =(3r+3r-4s)(3r-3r+4s) =(6r-4s)(4s) =8s(3r-2s)b)c2(c+2)-c-2 =c2(c+2)-(c+2) =(c2-1)(c+2) =(c+1)(c-1)(c+2)2a) (x+2)2-(x+2)(y-3)-6(y-3)2 let(x+2)be a,(y-3) be b =a2-ab-6b2 =(a-3b)(a+2b) =(x+2-3y+9)(x+2+2y-6) =(x-3y+11)(x-4+2y)b) 3(x+7)2+(x+7)(x-6)-14(x-6)2 let(x+7)be a,(x-6) be b =3a2+ab-14b2 =(3a+7b)(a-2b) =(3x+21+7x-42)(x+7-2x+12) =(10x-21)(19-x)3a) (k+1)2-(k+1)-56 =a2-a-56 =(a-8)(a+7) =(k-7)(k+8)b) (2x-3)2+10x-15 =4x2-12x+9+10x-15 =4x2-2x-6 =(2x-3)(2x+2) =2(2x-3)(x+1)
其他解答:
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