標題:
f.2 mathz ple help me~
發問:
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plz help me to answer the question.if you do not know the answer,plz answer no.i need the steep~thank for your help~ 1a)Factorize ab-bc. (b) Expand 2x(x+3)-5(x+3). (c)Using the result of (a) and (b),and let a+2x,b+x+3 and c+5,factorize 2x^2+x-15.
最佳解答:
I can help you: 1.Factorize ab-bc ab-bc =b(a-c) 2.Expand 2x(x+3)-5(x+3) *in the answer,you should put (x+3) at the front. 2x(x+3)-5(x+3) = (x+3)(2x-5) 3.Using the result of (a) and (b) ab-bc =b(a-c) 2x(x+3)-5(x+3) = (x+3)(2x-5) 2x^2+x-15 =2x^2+6x-5x-15 =2x(x+3)-5(x+3) =(x+3)(2x-5)
其他解答:
1a)Factorize ab-bc. =b(a-c) (b) Expand 2x(x+3)-5(x+3). =2x^2+6x-5x-15 =2x^2+x-15 (c)Using the result of (a) and (b),and let a+2x,b+x+3 and c+5,factorize 2x^2+x-15. by the result of (b) 2x^2+x-15 =2x(x+3)-5(x+3) Let a=2x, b=(x+3), c=5 By the result of (a) =2x(x+3)-5(x+3) =(x+3)(2x-5)|||||ab-bc =b(a-c)// 2x(x+3)-5(x+3) =(x+3)(2x-5)// 2x^2+x-15 =2x^2+6x-5x-15 =2x(x+3)-5(x+3) =(x+3)(2x-5)//
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