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標題:

(10分)中二數1題(不等式)

發問:

For two consecutive multiples of 3,5 times the larger number is not less than 2 times the smaller number plus 45. Find the minimum values of these two numbers. *Please show the famula and steps clearly.

最佳解答:

• 暑假去了那裡 (英文作文50字)
• 手臂同腳生一粒粒
• 有冇game適合20-30人玩(超急)

• 暑假去了那裡 (英文作文50字)
• 手臂同腳生一粒粒
• 有冇game適合20-30人玩(超急)

此文章來自奇摩知識+如有不便請留言告知

Let the smaller # be x . so, the larger # is (x 3). 5(x 3) ＞2x 45 5x 15 ＞2x 45 5x-2x＞45-15 3x ＞ 30 x ＞10 because they are consecutive multiples of 3,the minimum value of the smaller # must be 12, and the mi-nimum value of the larger # is 12 3=15.

其他解答:

Let the larger number and the smaller number be (x+3) and x respectively. 5(x+3) ＞ 2x+45 5x+15 ＞2x+45 3x ＞ 30 x ＞ 10 (because)They are consecutive multiples of 3. (so)The minimum value of the smaller number is 12, and the minimum value of the larger number is 12+3=15.