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標題:

F.4 Math joint variation

• ~ 證不等式 ~
• MU'Z 承諾既歌詞
• give a real-life example of a revolution

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發問:

Y varies jointly as x3 and √z where z ＞ 0, y= 96 when x = 2 and z = 16.(a) Express y in terms of xand z. Let y = ,where is a non-zeroconstant. When x = 2 and z = 16, y =96.(b) Find the value of z when x = 3 and y = 162.

最佳解答:

(a) Let y = kx3√z, where k is a non-zero constant. When x = 2 and z = 16, y = 96 : 96 = k(2)3√16 32k = 96 k = 3 Hence, y = 3x3√z (b) When x = 3 and y = 162 : (162) = 3(3)3√z 81√z = 162 √z = 2 z = 4

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